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Compare 2 Xml Files In C#카테고리 없음 2020. 3. 3. 16:09
C# Compare Two Xml Files
There are two immediate solutions:Solution 1.You can first apply a simple transform to the two documents that will delete the elements that should not be compared. Then, compare the results ing two documents - exactly with your current code. P.P.S.: A problem here would be that after doing the XSL transform of the two Xml documents, there will be no way to identify which player is which because the ranks of the player might change. The only way to match two players is by matching: 1. Their name and 2.
Their team, but those fields have been deleted after the transform. The only way to identify the players this way would be to refer to the two previous Xml documents and match the rank with the rank in the transformed Xml docs. Phhhheeeewww!!!–Jan 4 '11 at 18:14.
I was just wondering if there is a fast way to do this without having to manually go in and read the file.Not really.If the files came with hashes, you could compare the hashes, and if they are different you can conclude the files are different (same hashes, however, does not mean the files are the same and so you will still have to do a byte by byte comparison).However, hashes use all the bytes in the file, so no matter what, you at some point have to read the files byte for byte. And in fact, just a straight byte by byte comparison will be faster than computing a hash. This is because a hash reads all the bytes just like comparing byte-by-byte does, but hashes do some other computations that add time.
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Additionally, a byte-by-byte comparison can terminate early on the first pair of non-equal bytes.Finally, you can not avoid the need for a byte-by-byte read. If the hashes are equal, that doesn't mean the files are equal. In this case you still have to compare byte-by-byte. Hex codes d131dd02c5e6eec4693d9a0698aff95c 2fcab58712467eab4004583eb8fb7f89 55ad340609f4b32571415a 085125e8f7cdc99fd91dbdf280373c5b d88f5bae6dacd436c919c6 dd53e2b487da03fd02396306d248cda0 e99f33420f577ee8ce54b67080a80d1e c69821bcb6a88b6ff72a70 and d131dd02c5e6eec4693d9a0698aff95c 2fcab50712467eab4004583eb8fb7f89 55ad340609f4b325f1415a 085125e8f7cdc99fd91dbd7280373c5b d88f5bae6dacd436c919c6 dd53e23487da03fd02396306d248cda0 e99f33420f577ee8ce0d1e c69821bcb6a8839396f965ab6ff72a70 have the same md5 hash. They are not equal.–Oct 28 '11 at 15:53.